4x^2+64x-105=0

Solution for 4x^2+64x-105=0 equation:

4x^2+64x-105=0

a = 4; b = 64; c = -105;
Δ = b2-4ac
Δ = 642-4·4·(-105)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-76}{2*4}=\frac{-140}{8}
=-17+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+76}{2*4}=\frac{12}{8}
=1+1/2
$